Floating Point in Binary
Binary
0.010011two =
(0/2) + (1/22) + (0/24) +(1/25) + (1/26)
0 + 1/4 + 0 + 1/32 + 1/64 =
(0.25 + 0.03125 + 0.015625)ten =
0.296875ten
In scientific notation
10011*2-6 = 1001.1*2-5 =
100.11*2-4
1.0011*2-2 normalised
Previous slide
Next slide
Back to first slide
View graphic version