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Propergate Up Tree: Level 3


\begin{eqnarray*}M_3 = p'_{000} u_0 N +
p'_{200} u_0^2 N N +
p'_{220} (u_0^2 N) (u_0N) N +
p'_{222} (u_0^2 N) (u_0^2 N) N \\
\end{eqnarray*}


\psfig{height=0.4\textheight,figure=space_proof_pic/pnnn.eps}

Where p'iii refer to the proportion of children of the fourth node along the longest path (but excluding those on the longest path).



Bill LANGDON
2001-12-05